During the electrolysis of a salt of a metal M, a current...
During the electrolysis of a salt of a metal M, a current of 0.5 A flows from for 32 minutes 10 seconds and deposits 0.325 g of M, What is the charge of the metal ion?
(M = 65, If = 96,500 C per mole of electron)
1
2
3
4
Correct answer is B
Ampere = (Coulomb) x (Sec) x 1930 secs = 965 coulombs (unit of current)
But quantity of electricity = current x time = (Coulomb)/(Sec) x time
If 0.5 A for 32 mins 10 secs; Quantity of electricity = (0.5 coulomb)/(Sec x 1930) secs
= 965 coulombs
Since 965 coulombs give 0.325 g M
i.e1 coulombs = (0.325)/(965) g
∴96500 coulombs = (0.30)/(965) x 96500 =32.5 g
∴(65 g)/(32.5) = 2
inference: it takes 2 Faraday of electricity to deposit 1 mole of M. Therefore, the change on M ion = 2.
Which of the following is a condition for a spontaneous reaction? ...
The molar enthalpy change accompanying the removal of an electron from a gas phase atom or ion ...
To test for the presence of chloride ions in ion, correct sequence of reagents to use is ...
Which of the following are mixtures? I. Petroleum II. Rubber latex III. Vulcani...
200cm3 of 0.50mol/dm3 solution of calcium hydrogen trioxocarbonate (IV) is heated. The max...
The purity of a solid sample can best be determined by its ...