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8g CH4 occupies 11.2 dm3 at s.t.p. What volume would 22 g...

8g CH4 occupies 11.2 dm3 at s.t.p. What volume would 22 g of CH3CH2CH3 occupy under the same condition?

(C = 12, H = 1)

A.

3.7 dm3

B.

11.2 dm3

C.

22.4 dm3

D.

33.6 dm3

View answer & explanation

Correct answer is B

1 mole of any gas has a volume of 22.4dm3 at STP,  SO 1mole of propane = 44g = 22.4dm3

                                                                                                                              22g = ?

 ( 22 x 22.4)/ 44 = 11.2dm3

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