9.8g of solid potassium chlorate (KCIO₃) were added to 40 cm³ of water and heated to dissolve all the solid. As he solution cooled, crystals of potassium chlorate started forming at 60°C. The solubility of potassium chlorate at 66°C is therefore?

24.5 mole per dm³

0.2 mole per dm³

10.0 mole per dm³

20.0 mole per dm³

2.0 mole per dm³

Correct answer is E

9.8 gms KCIO₃ dissolves in 40 cm³ of H.
In 100 cc we have (9.8)/(40) x (100)/(1) = 24.5 gm KCIO₃

In 1000 cc we have 10 x 24.5
or 245 gms of KCIO₃.
But mol wt of KCIO₃ is 122.5
Solubility of KCIO₃ is (245)/(122.5) = 2 moles per dm³ (E)

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9.8g of solid potassium chlorate (KCIO₃) were added to 40 cm³ of water and heated to dissolve all the solid. As he solution cooled, crystals of potassium chlorate started forming at 60°C. The solubility of potassium chlorate at 66°C is therefore?

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9.8g of solid potassium chlorate (KCIO₃) were added to 40 cm³ of water and heated to dissolve all the solid. As he solution cooled, crystals of potassium chlorate started forming at 60°C. The solubility of potassium chlorate at 66°C is therefore?