0.07g of a hydride of carbon occupies 56.0cm³ at S.T.P. when vaporized and contains 14.29% by mass of hydrocarbon is(C = 12, H = 1)

CH₄

C₂H₂

C₂H₄

C₂H₆

C₃H₈

Correct answer is C

% of H₂ = 14.29
% of C = 85.71
Divided by At wts
For H = (14.29)/(1) = 14.29
For C = (85.71)/(12) = 7.14
Dividing by smallest number we have the following:
For H (14.29)/(7.14) = 2
For C = (7.14)/(7.14) = 1
Emperical formula of the comp = CH₂
wt of hydride taht will occupy 22400 cm is 22400 x 0.7
56 = 28 = mole wt of hydride
X(CH₂) = 28
X(12 + 2) = 28 i.e 14x = 28x = 2
The formula of hydrocarbon is therefore C₂H₄

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0.07g of a hydride of carbon occupies 56.0cm³ at S.T.P. when vaporized and contains 14.29% by mass of hydrocarbon is(C = 12, H = 1)

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0.07g of a hydride of carbon occupies 56.0cm3 at S.T.P. when vaporized and contains 14.29% by mass of hydrocarbon is(C = 12, H = 1)

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0.07g of a hydride of carbon occupies 56.0cm³ at S.T.P. when vaporized and contains 14.29% by mass of hydrocarbon is(C = 12, H = 1)