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If 24.83 cm3 of 0.15 M NaOH is titrated to its en...

If 24.83 cm3 of 0.15 M NaOH is titrated to its end point with 39.45 cm3
of HCl, what is the molarity of the HCl?

A.

0.094 M

B.

0.150 M

C.

0.940 M

D.

1.500 M

View answer & explanation

Correct answer is A

NaOH + HCl → NaCl + H2O moles ratio = 1/1
↔ (MaVa) / Mb x 39.45 = 0.094

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