0.1 Faraday of electricity was passed through a solution ...
0.1 Faraday of electricity was passed through a solution of copper (ll) sulphate. The maximum weight of copper deposited on the cathode would be [Cu = 64]
64.0g
32.0g
16.0g
6.4g
3.2g
Correct answer is E
CuSO4 \(\to\) Cu2+ + SO42+
Cu2+ + 2e \(\to\) Cu
1 Faraday will deposit \(\frac{64}{2}\)gms of copper
0.1 faraday will deposit \(\frac{64}{2} \times \frac{1}{10} = \frac{64}{20}\)
= \(\frac{32}{10}\) = 3.2gms
In which of the following processes is iron being oxidized? 1 Fe + H2SO4 → FeSO4 +H2 2 FeSO...
What is the major product formed when C2H5OH reacts with CH3COOH?...
Consider the reaction represented by the following equation: C2H4(g) + 302(g) → 2CO2(g) + 2H2O(g)...
In the reaction H2(g)O \(\to\) H2(g) + 1/2O2(g) ΔH = -2436000 KJ, which of the following has no ...
The boiling point of water is higher than the boiling point of ethanol because ...
Four elements W, X, Y and Z have atomic number 2,6,16 and 20 respectiv...