1
2
3
4
5
Correct answer is D
CuSO4 + 5H 2O
Wt CuSO4 + 5H2O = 14.98 - 10.00
= 4.98 gm
Wt of residue or CuSO4 = 13.54 - 10.00 =3.54
Wt of water lost = 4.98 - 3.54 = 1.44
Molecules of H2O lost = 5 - 1 = 4
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