Zn+H2SO4→ZnSO4+H2
in the...
Zn+H2SO4→ZnSO4+H2
in the above reaction, how much zinc will be left undissolved if 2.00g of zinc is treated with 10cm^3 of 1.0 M of H2SO4?
[Zn =65, s = 32, O = 16, H = 1]
1.35g
1.00g
0.70g
0.65g
0.00g
Correct answer is A
Zn+H2SO4→ZnSO4+H2
1 mole of Zn = 1 mole H2SO4
no of moles of H2SO4 = C X V = 1 X 10/1000 = 0.01moles.
0.01mole H2SO4 = 0.01 mole Zn
mass of Zn = 0.01 x 65(given) = 0.65g
therefore, the mass of undissolved Zn = 2.00(given) - 0.65 = 1.35g.
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