What volume of oxygen at s.t.p would react with carbon to form 4.40g of CO₂ according to the following equation? C_(s) + O_2(g) → CO_2(g) [O = 16; C =12; 1 mole of a gas occupies 22.4dm³ at s.t.p]

0.224dm³

2.24dm³

4.40dm³

4.48dm³

22.4dm³

Correct answer is B

From the equation, C + O₂ → CO₂ : 22.dm³ of oxygen is required to form 44g of CO₂ the volume of O₂ required to produce 4.4gm is x, :. x = ⁴⁴/₄₄ X 22.4dm³

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What volume of oxygen at s.t.p would react with carbon to form 4.40g of CO₂ according to the following equation? C_(s) + O_2(g) → CO_2(g) [O = 16; C =12; 1 mole of a gas occupies 22.4dm³ at s.t.p]

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What volume of oxygen at s.t.p would react with carbon to form 4.40g of CO2 according to the following equation? C(s) + O2(g) → CO2(g) [O = 16; C =12; 1 mole of a gas occupies 22.4dm3 at s.t.p]

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What volume of oxygen at s.t.p would react with carbon to form 4.40g of CO₂ according to the following equation? C_(s) + O_2(g) → CO_2(g) [O = 16; C =12; 1 mole of a gas occupies 22.4dm³ at s.t.p]