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One mole of a compound M(HCO₃)₂ has a ...

One mole of a compound M(HCO₃)₂ has a mass of 162g. Calculate the relative atomic mass of M. [H = 1, C =12, O = 16]

A.

122

B.

101

C.

53

D.

40

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Correct answer is D

One of the mole of M(HCO₃)₂ = 162g; M +(1 + 12 + 16 x 3) x 2 = 162; M +122 = 162,:. M = 162 - 122 = 40g

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