30cm3 pf hydrogen at s.t.p combine with 20cm3 of oxygen to form steam according to the following equation 2H2(g) + O2(g) → 2H2O(g).

Calculate the total volume of the gaseous mixture at the end of the reaction

50cm³

35cm³

30cm³

25cm³

Correct answer is B

2H $_2$ (g) + O $_2$ (g) → 2H $_2$ O(g).

2 volumes of H $_2$ (g) and 1 volume of O $_2$ (g) produced 2 volumes of H $_2$ O $_2$

ratio of reacting volumes

30cm $^3$ + 15cm $^3$ → 30cm $^3$

30cm $^3$ of Hydrogen requires 15cm $^3$ of oxygen to produce 30cm $^3$ of water.

Excess oxygen: 20cm $^3$ – 15cm $^3$ = 5cm $^3$

Total volume of gaseous mixture: 5cm $^3$ of Oxygen + 30cm $^3$ of Water = 35cm $^3$

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30cm3 pf hydrogen at s.t.p combine with 20cm3 of oxygen to form steam according to the following equation 2H2(g) + O2(g) → 2H2O(g).

Calculate the total volume of the gaseous mixture at the end of the reaction

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30cm3 pf hydrogen at s.t.p combine with 20cm3 of oxygen to form steam according to the following equation 2H2(g) + O2(g) → 2H2O(g). Calculate the total volume of the gaseous mixture at the end of the reaction

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Aptitude Tests

30cm3 pf hydrogen at s.t.p combine with 20cm3 of oxygen to form steam according to the following equation 2H2(g) + O2(g) → 2H2O(g).

Calculate the total volume of the gaseous mixture at the end of the reaction