14.8 g of a salt (z)dissolved in 250 cm³ of distilled water gives a concentration of 0.80 mol dm^-3. Calculate the molar mass of the salt (z).

13.5 g mol^-1

18.5 g mol^-1

47.4 g mol^-1

74.0 g mol^-1

Correct answer is D

250cm³ of distilled water contains 14.8g of salt(z)
1cm³ of distilled water will contain \(\frac{14.8 x 1}{250}\) of salt (z)
:. 1000cm³ of distilled water will contain \(\frac{14.8 x 1 x 1000}{250}\) = 59.2g/dm³3 = \(\frac{concentration in g/dm³}{molar mass}
0.80 = \(\frac{59.2}{molar mass}\)
molar mass = \(\frac{59.2}{0.80}\) = 74.0 g/mol

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14.8 g of a salt (z)dissolved in 250 cm³ of distilled water gives a concentration of 0.80 mol dm^-3. Calculate the molar mass of the salt (z).

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14.8 g of a salt (z)dissolved in 250 cm3 of distilled water gives a concentration of 0.80 mol dm-3. Calculate the molar mass of the salt (z).

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14.8 g of a salt (z)dissolved in 250 cm³ of distilled water gives a concentration of 0.80 mol dm^-3. Calculate the molar mass of the salt (z).