The volume of 0.25 moldm-3 solution of KOH that would yie...
The volume of 0.25 moldm-3 solution of KOH that would yield 6.5g of of solid KOH on evaporation is (K = 39.0; o = 16.0; H = 1.00)
464.30 cm3
625.00 cm3
1000.00 cm3
2153.80 cm3
Correct answer is A
number of moles = molar concentration x volume(dm3)
molar concentration(C) = 0.25mol/dm3, volume = ? and number of mole(n) = massmolarmass = 6.556 ( where 56g/mol = molar mass of KOH)
6.556 = 0.25 x V
V = 0.116070.25 = 0.46428dm^3 → 464.3cm^3
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