Consider the following reaction equation: CaCO3(s)...
Consider the following reaction equation: CaCO3(s) + 2HCI(aq) → CaCl2(aq) + H2O(l) + CO2(g). What mass of CaCI2 would be obtained when 25.0g of CaCO3(s) is reacted with excess HCI(aq)? [CaCO3=100;CaCI\(2 = 111]
4.00g
4.44 g
18.9 g
27.8 g
Correct answer is D
CaCO3 + 2HCI → CaCI2 + H2O + CO2
100g CaCO3 will produce 111g CaCI2
25g CaCO3 will produce x ,
x = 25x111100
= 27.75 ≊ 27.8g