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Consider the following reaction equation: CaCO3(s)...

Consider the following reaction equation: CaCO3(s) + 2HCI(aq) → CaCl2(aq) + H2O(l) + CO2(g). What mass of CaCI2 would be obtained when 25.0g of CaCO3(s) is reacted with excess HCI(aq)? [CaCO3=100;CaCI\(2 = 111]

A.

4.00g

B.

4.44 g

C.

18.9 g

D.

27.8 g

Correct answer is D

CaCO3 + 2HCI → CaCI2 + H2O + CO2

100g CaCO3 will produce 111g CaCI2

25g CaCO3 will produce x ,

x = 25x111100

= 27.75  27.8g