\(Cu_2S_{(s)}+ O_{2(g)} = 2CU_{(s)} + SO_{2(g)}\).
<...\(Cu_2S_{(s)}+ O_{2(g)} = 2CU_{(s)} + SO_{2(g)}\).
In the above reaction, the oxidation number of Cu changes from ___ to _______?
+1 to 0
0 to +2
+2 to +1
0 to +1
Correct answer is A
The oxidation number is from +1 to O as a result of the release of sulphur. Options B, C, and D are not the actual oxidation number for copper
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