The oxidation number of X in \(XO_{4}^{3-}\) is
...The oxidation number of X in \(XO_{4}^{3-}\) is
1
-2
3
4
5
Correct answer is E
The oxidation number of O is 2-
Therefore, let the oxidation number of X be a
a + (-2 x 4) = -3
a - 8 = -3
a = -3+8
a = 5
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