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MnO4(aq) + 8H + 5Fe2+ $\to$ Mn2+(aq) + 5Fe3+(aq) + H2O. Th...

MnO4(aq) + 8H + 5Fe2+ $\to$ Mn2+(aq) + 5Fe3+(aq) + H2O. The oxidation number of maganese in the above reaction changed from

A.

+7 to +2

B.

+6 to +2

C.

+5 to +2

D.

+4 to +2

View answer & explanation

Correct answer is A

$MnO_{{4}{(aq)}}$ has a charge of $-1$

Let the oxidation number of $Mn$ in $MnO_{{4}{(aq)}}$ be X

Recall, the oxidation number of $O_{2}$ is $-2$

$\therefore$ $X + (-2\times 4) = -1$

$X - 8 = -1$

$X = +7$

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