1.00g of mixture of calcium carbonate and calcium oxide l...
1.00g of mixture of calcium carbonate and calcium oxide liberated 0.33g of carbon dioxide on strong heating. The percentage of calcium oxide in the mixture is? (Ca = 40, C = 12, O = 16)
5
15
25
35
50
Correct answer is C
CaCO3 + CaO \(\to\) 2CaO + 2CO2
44gm of CO3 is liberated by 100gm of CaCO3
0.33gm of CO2 will be liberated by \(\frac{100}{44}\) x 0.33
= 0.75 of CaCO3
Amount of CaO = 1 - 0.75
= 0.25
% of CaO = \(\frac{0.25}{1} \times \frac{100}{1}\)
= 25%
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