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What volume of 0.5M H2SO4 will exactly neutralize 20cm3 o...

What volume of 0.5M H2SO4 will exactly neutralize 20cm3 of 0.1M NaOH Solution?

A.

2.0cm ³

B.

5.0cm ₃

C.

6.8cm ³

D.

8.3cm ³

View answer & explanation

Correct answer is A

The balanced equation is given as:

$H_{2}SO_{4} + 2NaOH \to Na_{2}SO_{4} + 2H_{2}O$

Molarity of $NaOH = 0.1M$

Volume of $NaOH = 20cm^{3}$

Molarity of $H_{2}SO_{4} = 0.5M$

mol NaOH = $0.1 \times 20cm^{3} = 2molNaOH$

⇒ $2mol NaOH \times \frac{1mol H_{2}SO_{4}}{2mol NaOH} = 1 mol H_{2}SO_{4}$

$volume of H_{2}SO_{4} = \frac{mole of H_{2}SO_{4}}{molarity of H_{2}SO_{4}}$

= $\frac{1 mole}{0.5 M} = 2cm^{3} H_{2}SO_{4}$

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