On evaporation to dryness, 3503 of saturated solution of salt Z gave 55.5g of salt. What is the solubility of the salt? [Z = 101]
A.
1.57 moldm-3
B.
3.14 moldm-3
C.
6.28 moldm-3
D.
12.56 moldm-3
Correct answer is A
Saturated solution = 3503
mass of salt Z in saturated solution = 55.5g
Number of moles of salt = \(\frac{55.5}{101}\) = 0.55mole
3503 of solution contains 0.55mole
1000cm3 will contain \(\frac{1000 \times 0.55}{350}\) = 1.57mol/dm3
