The mass of silver deposited when a current of 10A is pas...
The mass of silver deposited when a current of 10A is passed through a solution of silver salt for 4830s is – (Ag = 108 F = 96500(mol-1)
54.0g
27.0g
13.5g
108.0gQ
Correct answer is A
Recall that
mass deposited = \(\frac{MmIt}{96500n}\)
Mm =108, t = 4830s
I = 10A, n = 1
m = 108 × 10 × (\(\frac{4830}{96500}\)) × 1
m = 54.0g
A mixture of iron and sulphur can be separated by dissolving the mixture in? ...
The basic particles from which matter could be made up of are as follow, except? ...
Consider the following exothermic reaction 2SO2(g) + O2(g) ↔ 2SO3(g) If the temperature of the r...
Hydration of ions in solution is associated with...
When sugar is dissolved in tea, the reaction is always accomplished by ...