3.30
13.00
10.70
11.30
Correct answer is A
PH+POH=14
pH = Log [H+]
p[H+ ] = 2.0 X 10−11moldm−3
pH = Log [2.0 X 10−11]
pH = 10.70
10.70+ pOH =14
pOH = 14 -10.70
= 3.30
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