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The oxidation number of nitrogen in $Pb(NO_{3})_{2}$ is...

The oxidation number of nitrogen in $Pb(NO_{3})_{2}$ is

A.

+2

B.

+3

C.

+4

D.

+5

View answer & explanation

Correct answer is D

$Pb(NO_{3})_{2}$ = $+2 +2N + (-2\times 6) = 0$

= $2N = 10$

⇒ $N = +5$

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