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The number of atoms present in 2.5moles of a triatomic gas i...

The number of atoms present in 2.5moles of a triatomic gas is equivalent to [1mole = $6.02\times 10^{23}$ ]

A.

$2.5\times 10^{23}$

B.

$1.5\times 10^{23}$

C.

$1.5\times 10^{24}$

D.

$2.5\times 10^{24}$

View answer & explanation

Correct answer is C

1 mole = $6.02 \times 10^{23}$

2.5 moles = $6.02 \times 10^{23} \times 2.5$

= $15.05 \times 10^{23} = 1.505 \times 10^{24}$

$\approxeq 1.5 \times 10^{24}$

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