Consider the equation below:
Cr2O\(_7 ^{2-}\...
Consider the equation below:
Cr2O2−7 + 6Fe2+ + 14H+ → 2Cr3+ + 6Fe3+ + 7H2O.
The oxidation number of chromium changes from
+5 to +3
+6 to +3
-2 to +3
+7 to +3
Correct answer is B
Cr2O2−7 + 6Fe2+ + 14H+ → 2Cr3+ + 6Fe3+ + 7H2O
The oxidation of Cr in Cr2O2−7 :
Let the oxidation of Cr = x;
2x + (-2 x 7) = -2 ⟹ 2x - 14 = -2
2x = 12 ; x = +6
Hence, the change in oxidation of Cr = +6 to +3
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