The oxidation state(s) of nitrogen in ammonium nitrite is...
The oxidation state(s) of nitrogen in ammonium nitrite is/are
-3, +3
+5
-3, +5
-3
Correct answer is A
Ammonium nitrite = NH4NO2
NH+4: Let the oxidation number of Nitrogen = x
x + 4 = 1 ⟹ x = 1 - 4
x = -3
NO−2: x - 4 = -1
x = -1 + 4 ⟹ x = +3.
The oxidation numbers for Nitrogen in Ammonium Nitrite = -3, +3.
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