f 5.0 cm−3 of 0.200 mol dm(^-3\) Na2C...
f 5.0 cm−3 of 0.200 mol dm(^-3\) Na2CO3 was diluted to 250cm(^-3\) solution, what would be the concentration of the resulting solution?
0.004 mol dm(^-3\)
0.020 mol dm(^-3\)
0.200 mol dm(^-3\)
0.400 mol dm(^-3\)
Correct answer is A
= | initial molarity | |
= | initial volume in liters | |
= | final molarity | |
= | final volume in liters |
0.200 X 5.00 = M2 X 250
M2 = 1 / 250
M2 = 0.004 mol dm(^-3\)
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