Arrange the following compounds in decreasing order of their boiling points: $NH_3$ , HF, $SiH_4$ , $CH_4$

HF, $NH_3$ , $SiH_4$ , $CH_4$

$CH_4$ , $SiH_4$ , HF, $NH_3$ ,

$NH_3$ , $CH_4$ , $SiH_4$ , HF

$CH_4$ , $SiH_4$ , $NH_3$ , HF

Correct answer is A

The correct order of boiling points of the compounds $NH_3$ , HF, $SiH_4$ , and $CH_4$ is HF, $NH_3$ , $SiH_4$ , $CH_4$ .
The correct order of boiling points of the compounds $NH_3$ , HF, $SiH_4$ , and $CH_4$ is HF, $NH_3$ , $SiH_4$ , $CH_4$ .

The boiling point of a compound is the temperature at which the vapor pressure of the liquid is equal to the atmospheric pressure. The stronger the intermolecular forces, the higher the boiling point.

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