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Solve 32x3x+2=3x+127...

Solve 32x3x+2=3x+127

A.

1 or 0

B.

1 or 2

C.

1 or -2

D.

-1 or 2

Correct answer is B

32x3x+2=3x+127

= (3x)2(3x).(32)=(3x).(31)27

Let 3x be B; we have

= B29B3B+27=B212B+27=0.

Solving the equation, we have B = 3 or 9.

3x=3 or 3x=9

3x=31 or 3x=32

Equating, we have x = 1 or 2.