−15a4b2
15a4b2
−15a3b3
15a3b3
Correct answer is B
(a−b)6=6C0(a)6(−b)0+6C1(a)5(−b)1+6C2(a)4(−b)2+...
Third term = 6C2(a)4(−b)2=6!(6−2)!2!(a4)(b2)
= 15a4b2
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