3x3(3x3+1)
3x23√(3x3+1)2
3x3√3x2+1
3x23(3x2+1)2
Correct answer is B
y=3√3x3+1=(3x3+1)13
Let u = 3x3+1; y = u13
dydx=(dydu)(dudx)
dydu=13u−23
dudx=9x2
dydx=(13(3x3+1)−23)(9x2)
= 3x23√(3x3+1)2
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