27√2
27√6
81√2
81√6
Correct answer is C
Tn=arn−1 (Geometric progression)
a=√6,r=T2T1=3√2√6
r=√18√6=√3
∴
= (\sqrt{6})(27\sqrt{3}) = 27\sqrt{18} = 81\sqrt{2}
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