13
49
59
1
Correct answer is A
Differentiate distance twice to get the acceleration and then equate to get p.
s=7+pt3+t2
dsdt=v(t)=3pt2+2t
dvdt=a(t)=6pt+2
a(3)=6p(3)+2=8⟹18p=8−2=6
p=618=13
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