x<−1,x<−13
x>−1,x>−13
x>13,x<−1
x<13,x>−1
Correct answer is B
3x2+4x+1>0
3x2+3x+x+1>0
3x(x+1)+1(x+1)>0
(3x+1)(x+1)>0
3x+1>0⟹3x>−1
x>−13
x+1>0⟹x>−1
x>−1,x>−13
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