x2+y2−4x−6y−12=0
x2+y2−4x+6y−12=0
x2+y2+4x+6y−12=0
x2+y2+4x−6y−12=0
Correct answer is D
Equation of a circle with centre coordinates (a, b) : (x−a)2+(y−b)2=r2
Area of circle = πr2=25πcm2⟹r2=25
∴
(a, b) = (-2, 3)
Equation: (x - (-2))^{2} + (y - 3)^{2} = 5^{2}
x^{2} + 4x + 4 + y^{2} - 6y + 9 = 25 \implies x^{2} + y^{2} + 4x - 6y + 13 - 25 = 0
= x^{2} + y^{2} + 4x - 6y - 12 = 0
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