-4
\(-\frac{1}{4}\)
\(\frac{1}{8}\)
4
Correct answer is D
\((\frac{-1}{64})^{\frac{-2}{3}} = -64^{\frac{2}{3}}\)
\((-4^{3})^{\frac{2}{3}} = -4^{2} = 16\)
\(\therefore \sqrt{(\frac{-1}{64})^{\frac{-2}{3}} = \sqrt{16} = 4\)
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