Given that \(\frac{1}{x^2 - 4} = \frac{p}{(x + 2)} + \fra...
Given that 1x2−4=p(x+2)+Q(x−2)
x ≠±2
Find the value of (P + Q)
32
1
12
0
Correct answer is D
1x2−4=P(x+2)+Q(x−2)
I = p(x - 2) + Q(x + 2)
Let x = 2
I = P(2 - 2) + Q(2+ 2)
I = -4Q
Q = 14
Let x = -2
I = P(-2 - 2) + Q(-2 + 2)
I = -4p
P = 1−4
PQQ = - 14+14
= 0
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