Find the equation of the straight line that passes throug...
Find the equation of the straight line that passes through (2, -3) and perpendicular to the line 3x - 2y + 4 = 0.
2y - 3x = 0
3y - 2x + 5 = 0
3y + 2x + 5 = 0
2y - 3x - 5 = 0
Correct answer is C
Given line: 3x−2y+4=0⟹2y=3x+4
y=32x+2
Gradient(dydx)=32
Gradient of perpendicular line = −132=−23
⟹y−(−3)x−2=−23
y+3x−2=−23
3(y+3)=−2(x−2)⟹3y+2x+9−4=0
= 3y+2x+5=0
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