Two fair dices, each numbered 1, 2, ..., 6, are tossed to...
Two fair dices, each numbered 1, 2, ..., 6, are tossed together. Find the probability that they both show even numbers.
\(\frac{1}{3}\)
\(\frac{1}{4}\)
\(\frac{1}{6}\)
\(\frac{1}{12}\)
Correct answer is B
P(even in 1 dice) = \(\frac{3}{6} = \frac{1}{2}\)
P(even in 2 fair die) = \(\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}\)
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