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If log10(3x+1)+log104=log10(9x+2)...

If log10(3x+1)+log104=log10(9x+2), find the value of x 

A.

13

B.

1

C.

2

D.

3

Correct answer is C

log10(3x+1)+log104=log10(9x+2)

log104(3x+1)=log10(9x+2)

4(3x+1) = 9x + 2

12x -4 = 9x + 2

12x - 9x = 2 + 4

3x = 6

x = 2