If log 10 to base 8 = X, evaluate log 5 to base 8 in term...
If log 10 to base 8 = X, evaluate log 5 to base 8 in terms of X.
12X
X-14
X-13
X-12
Correct answer is C
log810 = X = log82x5
log82 + log85 = X
Base 8 can be written as 23
log82=y
therefore 2=8y
y=13
13=log82
taking 13 to the other side of the original equation
log85=X−13
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