Factorize completely; (4x+3y)\(^2\) - (3x-2y)\(^2\) ...
Factorize completely; (4x+3y)\(^2\) - (3x-2y)\(^2\)
(x+5y)(7x+y)
(x+5y)(7x-y)
(x-5y)(7x+y)
(x-5y)(7x-y)
Correct answer is A
(4x+3y)\(^2\) - (3x-2y)\(^2\)
Using the differences of two squares:
(4x+3y+3x-2y)(4x+3y-(3x-2y))
(4x+3y+3x-2y)(4x+3y-3x+2y)
(x+5y)(7x+y)
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