If a load of mass 10N stretched a cord by 1.2cm, what is ...
If a load of mass 10N stretched a cord by 1.2cm, what is the total work done?
6.0 x 10-2J
7.6 x 10-2J
1.8 x 10-2J
6.6 x 10-2J
Correct answer is A
Work done on a stretched cord
= Average force x extension
= 1×10×0.0122
= 6.0 x 10−2J
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