If sinθ = K find tanθ, 0° \(...
If sinθ = K find tanθ, 0° ≤ θ ≤ 90°.
1-K
kk−1
k√1−k2
k1−k
k√k2−1
Correct answer is C
sinθ=k1
⟹12=k2+adj2
adj=√1−k2
∴
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