Points P and Q respectively 24m north and 7m east point R...
Points P and Q respectively 24m north and 7m east point R. What is the bearing of Q from P to the nearest whole degree?
16o
17o
73o
106o
164o
Correct answer is E
Using pythagoras' theorem:
Hyp2 = Adj2 + Opp2 → 242 + 72
Hyp = √625 → 25
tanP=724
tanP=0.2917
P=tan−1(0.2917)
= 16.26°
Bearing of Q from P = 180° - 16.26°
= 163.74° ≊ 164°
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