In the diagram O is the center of the circle, if ∠QRS...
In the diagram O is the center of the circle, if ∠QRS = 62o, find the value of ∠SQR.
14o
28o
31o
45o
90o
Correct answer is B
< QSR = 90° (angle in a semi-circle)
\(\therefore\) < SQR = 180° - (90° + 62°)
= 28°
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