x+31−x2
3−x(1−x)2
3−x1+x2
3−x(1+x)2
3−x1−x2
Correct answer is E
11−x+21+x
= (1+x)+2(1−x)(1−x)(1+x)
= 1+x+2−2x1−x2
= 3−x1−x2
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