What amount of current would pass through a 10 Ω co...
What amount of current would pass through a 10 Ω coil if it takes 21s for the coil to just melt a lump of ice of mass 10g at 0oC if there are no heat losses? (Latent heat of fusion of ice = 336 Jg−1).
16.00A
4.00A
0.50A
0.25A
0.06A
Correct answer is B
I2Rt = mI;
I = √mIRt
= √10×33610×21
= √16
= 4.0A