Hot water at a temperature of t is added to twice that am...
Hot water at a temperature of t is added to twice that amount of water at a temperature of 30°C. If the resulting temperature of the mixture is 50°C. Calculate t.
90oC
80oC
50oC
40oC
30oC.
Correct answer is A
Final Temperature = m1T1+m2T2m1+m2
where m1 and m2 are the weights of the water in the first and second containers.
T1 and T2 are the temperatures of the water in the first and second container.
Given Final temperature = 50°C;
Let m1 = b, then m2 = 2b.
T1 = t; T2 = 30°C
∴
50 = \frac{bt + 2b(30)}{3b}
50(3b) = bt + 2b(30) \implies 150b = b(t + 60)
150 = t + 60 \implies t = 150 - 60 = 90°C
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