The energy stored in a capacitor of capacitance 5μF is...
The energy stored in a capacitor of capacitance 5μF is 40J. Calculate the voltage applied across its terminals?
4000V
200V
16V
6V
4V
Correct answer is A
E=CV22
V2=2EC
V2=2×405×10−6
V2=16×106
V=4×103=4000v
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