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The energy stored in a capacitor of capacitance 5μF is...

The energy stored in a capacitor of capacitance 5μF is 40J. Calculate the voltage applied across its terminals?

A.

4000V

B.

200V

C.

16V

D.

6V

E.

4V

View answer & explanation

Correct answer is A

$E = \frac{CV^{2}}{2}$

$V^{2} = \frac{2E}{C}$

$V^{2} = \frac{2\times 40}{5 \times 10^{-6}}$

$V^{2} = 16 \times 10^{6}$

$V = 4 \times 10^{3} = 4000v$

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